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Math Prodigy's #13519391 04/15/20 06:33 PM
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Bigbob_FTW Offline OP
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I need to find the center of an arc. known are the endpoints, radius and direction. go!


[Linked Image][Linked Image] FJB
Re: Math Prodigy's [Re: Bigbob_FTW] #13519400 04/15/20 06:38 PM
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Draw a straight line between the arc's two endpoints. Then mark a line through the centerpoint that is perpendicular to the baseline you put between the endpoints. That line will intersect the halfway point of the arc. No measurements are required other than making the 90 degree angle.

Re: Math Prodigy's [Re: Bigbob_FTW] #13519402 04/15/20 06:39 PM
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that's where Noah kept the elephants. Gave the boat stability.


Just want to make folks smile, and spit coffee on their keyboard.

If you put beans in your chili, you don't know beans about chili.

God doesn't create temporary people, you will spend eternity somewhere. Choose wisely.
Re: Math Prodigy's [Re: Flippin-Out] #13519404 04/15/20 06:39 PM
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Originally Posted by Flippin-Out
Draw a straight line between the arc's two endpoints. Then mark a line through the centerpoint that is perpendicular to the baseline you put between the endpoints. That line will intersect the halfway point of the arc. No measurements are required other than making the 90 degree angle.



forgot to mention, I'm doing this programatically.


[Linked Image][Linked Image] FJB
Re: Math Prodigy's [Re: Bigbob_FTW] #13519406 04/15/20 06:41 PM
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Radius Pie squared times tangent equals, I'm confused.

Re: Math Prodigy's [Re: Bigbob_FTW] #13519412 04/15/20 06:45 PM
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Originally Posted by Bigbob_FTW
Originally Posted by Flippin-Out
Draw a straight line between the arc's two endpoints. Then mark a line through the centerpoint that is perpendicular to the baseline you put between the endpoints. That line will intersect the halfway point of the arc. No measurements are required other than making the 90 degree angle.



forgot to mention, I'm doing this programatically.


Recommend using a computer.

Re: Math Prodigy's [Re: Bigbob_FTW] #13519424 04/15/20 06:54 PM
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I can count to 100 by fives, if that helps ,, smile


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MY BACKYARD , 20,000 ACRES , NO MOWING smile
Re: Math Prodigy's [Re: Bigbob_FTW] #13519426 04/15/20 06:57 PM
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*prodigies *

Re: Math Prodigy's [Re: Siberman] #13519428 04/15/20 06:58 PM
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Originally Posted by Siberman
*prodigies *


I said math, not english! whip


[Linked Image][Linked Image] FJB
Re: Math Prodigy's [Re: Bigbob_FTW] #13519470 04/15/20 07:18 PM
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Originally Posted by Bigbob_FTW
Originally Posted by Flippin-Out
Draw a straight line between the arc's two endpoints. Then mark a line through the centerpoint that is perpendicular to the baseline you put between the endpoints. That line will intersect the halfway point of the arc. No measurements are required other than making the 90 degree angle.



forgot to mention, I'm doing this programatically.

So you have a virtual arc on a 2D grid I gather? I understand you have endpoints (as x,y coordinates)? radious, and center. What do you mean by direction?
Depending on what data is available from your grid, will it give you an angle if you put a radius from the center to each endpoint? That angle divided by 2 will allow you to calculate the direction of a radius tot the center of the arc.

Re: Math Prodigy's [Re: Flippin-Out] #13519483 04/15/20 07:28 PM
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Originally Posted by Flippin-Out
Originally Posted by Bigbob_FTW
Originally Posted by Flippin-Out
Draw a straight line between the arc's two endpoints. Then mark a line through the centerpoint that is perpendicular to the baseline you put between the endpoints. That line will intersect the halfway point of the arc. No measurements are required other than making the 90 degree angle.



forgot to mention, I'm doing this programatically.

So you have a virtual arc on a 2D grid I gather? I understand you have endpoints (as x,y coordinates)? radious, and center. What do you mean by direction?
Depending on what data is available from your grid, will it give you an angle if you put a radius from the center to each endpoint? That angle divided by 2 will allow you to calculate the direction of a radius tot the center of the arc.


we use direction for G code
G2 is an arc, Clockwise
G3 is an arc, CClockwise

in the first pic is a G3. the Second is a G2 so the start and end points flip with direction.

[Linked Image]
[Linked Image]

Hope this helps.


[Linked Image][Linked Image] FJB
Re: Math Prodigy's [Re: Bigbob_FTW] #13519485 04/15/20 07:29 PM
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Re: Math Prodigy's [Re: Bigbob_FTW] #13519494 04/15/20 07:35 PM
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Looking at either illustration, do you know the x/y coordinates of each of the 3 points connected by the dashed lines?
And the goal is to calculate x/y coordinates of the floating point?

Last edited by Flippin-Out; 04/15/20 07:36 PM.
Re: Math Prodigy's [Re: Flippin-Out] #13519503 04/15/20 07:42 PM
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Bigbob_FTW Offline OP
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Originally Posted by Flippin-Out
Looking at either illustration, do you know the x/y coordinates of each of the 3 points connected by the dashed lines?
And the goal is to calculate x/y coordinates of the floating point?


[Linked Image]


[Linked Image][Linked Image] FJB
Re: Math Prodigy's [Re: Bigbob_FTW] #13519509 04/15/20 07:47 PM
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Ahhh, you need the center of a circle that includes an arc, NOT the centerpoint along the length of an arc. Those are two different solutions. I'll sharpen my crayon with the illustration in front of me.

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