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Math Prodigy's
#13519391
04/15/20 06:33 PM
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Joined: Oct 2006
Posts: 96,187
Bigbob_FTW
OP
Big Sprocket Bob
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OP
Big Sprocket Bob
Joined: Oct 2006
Posts: 96,187 |
I need to find the center of an arc. known are the endpoints, radius and direction. go!
FJB
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Re: Math Prodigy's
[Re: Bigbob_FTW]
#13519400
04/15/20 06:38 PM
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Joined: Feb 2015
Posts: 4,730
Flippin-Out
TFF Team Angler
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TFF Team Angler
Joined: Feb 2015
Posts: 4,730 |
Draw a straight line between the arc's two endpoints. Then mark a line through the centerpoint that is perpendicular to the baseline you put between the endpoints. That line will intersect the halfway point of the arc. No measurements are required other than making the 90 degree angle.
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Re: Math Prodigy's
[Re: Bigbob_FTW]
#13519402
04/15/20 06:39 PM
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Joined: Mar 2015
Posts: 12,218
UGLYSHCTICK
TFF Guru
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TFF Guru
Joined: Mar 2015
Posts: 12,218 |
that's where Noah kept the elephants. Gave the boat stability.
Just want to make folks smile, and spit coffee on their keyboard.
If you put beans in your chili, you don't know beans about chili.
God doesn't create temporary people, you will spend eternity somewhere. Choose wisely.
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Re: Math Prodigy's
[Re: Flippin-Out]
#13519404
04/15/20 06:39 PM
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Joined: Oct 2006
Posts: 96,187
Bigbob_FTW
OP
Big Sprocket Bob
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OP
Big Sprocket Bob
Joined: Oct 2006
Posts: 96,187 |
Draw a straight line between the arc's two endpoints. Then mark a line through the centerpoint that is perpendicular to the baseline you put between the endpoints. That line will intersect the halfway point of the arc. No measurements are required other than making the 90 degree angle. forgot to mention, I'm doing this programatically.
FJB
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Re: Math Prodigy's
[Re: Bigbob_FTW]
#13519406
04/15/20 06:41 PM
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Joined: Apr 2017
Posts: 12,116
BCBassCat
TFF Guru
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TFF Guru
Joined: Apr 2017
Posts: 12,116 |
Radius Pie squared times tangent equals, I'm confused.
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Re: Math Prodigy's
[Re: Bigbob_FTW]
#13519412
04/15/20 06:45 PM
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Joined: Jul 2007
Posts: 51,007
Trickster
Super Freak
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Super Freak
Joined: Jul 2007
Posts: 51,007 |
Draw a straight line between the arc's two endpoints. Then mark a line through the centerpoint that is perpendicular to the baseline you put between the endpoints. That line will intersect the halfway point of the arc. No measurements are required other than making the 90 degree angle. forgot to mention, I'm doing this programatically. Recommend using a computer.
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Re: Math Prodigy's
[Re: Bigbob_FTW]
#13519424
04/15/20 06:54 PM
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Joined: Oct 2001
Posts: 15,336
Mo
TFF Guru
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TFF Guru
Joined: Oct 2001
Posts: 15,336 |
I can count to 100 by fives, if that helps ,, MO
MY BACKYARD , 20,000 ACRES , NO MOWING
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Re: Math Prodigy's
[Re: Siberman]
#13519428
04/15/20 06:58 PM
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Joined: Oct 2006
Posts: 96,187
Bigbob_FTW
OP
Big Sprocket Bob
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OP
Big Sprocket Bob
Joined: Oct 2006
Posts: 96,187 |
I said math, not english!
FJB
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Re: Math Prodigy's
[Re: Bigbob_FTW]
#13519470
04/15/20 07:18 PM
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Joined: Feb 2015
Posts: 4,730
Flippin-Out
TFF Team Angler
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TFF Team Angler
Joined: Feb 2015
Posts: 4,730 |
Draw a straight line between the arc's two endpoints. Then mark a line through the centerpoint that is perpendicular to the baseline you put between the endpoints. That line will intersect the halfway point of the arc. No measurements are required other than making the 90 degree angle. forgot to mention, I'm doing this programatically. So you have a virtual arc on a 2D grid I gather? I understand you have endpoints (as x,y coordinates)? radious, and center. What do you mean by direction? Depending on what data is available from your grid, will it give you an angle if you put a radius from the center to each endpoint? That angle divided by 2 will allow you to calculate the direction of a radius tot the center of the arc.
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Re: Math Prodigy's
[Re: Flippin-Out]
#13519483
04/15/20 07:28 PM
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Joined: Oct 2006
Posts: 96,187
Bigbob_FTW
OP
Big Sprocket Bob
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OP
Big Sprocket Bob
Joined: Oct 2006
Posts: 96,187 |
Draw a straight line between the arc's two endpoints. Then mark a line through the centerpoint that is perpendicular to the baseline you put between the endpoints. That line will intersect the halfway point of the arc. No measurements are required other than making the 90 degree angle. forgot to mention, I'm doing this programatically. So you have a virtual arc on a 2D grid I gather? I understand you have endpoints (as x,y coordinates)? radious, and center. What do you mean by direction? Depending on what data is available from your grid, will it give you an angle if you put a radius from the center to each endpoint? That angle divided by 2 will allow you to calculate the direction of a radius tot the center of the arc. we use direction for G code G2 is an arc, Clockwise G3 is an arc, CClockwise in the first pic is a G3. the Second is a G2 so the start and end points flip with direction. Hope this helps.
FJB
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Re: Math Prodigy's
[Re: Bigbob_FTW]
#13519485
04/15/20 07:29 PM
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Joined: Jan 2005
Posts: 120,151
TexDawg
Top Dawg
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Top Dawg
Joined: Jan 2005
Posts: 120,151 |
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Re: Math Prodigy's
[Re: Bigbob_FTW]
#13519494
04/15/20 07:35 PM
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Joined: Feb 2015
Posts: 4,730
Flippin-Out
TFF Team Angler
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TFF Team Angler
Joined: Feb 2015
Posts: 4,730 |
Looking at either illustration, do you know the x/y coordinates of each of the 3 points connected by the dashed lines? And the goal is to calculate x/y coordinates of the floating point?
Last edited by Flippin-Out; 04/15/20 07:36 PM.
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Re: Math Prodigy's
[Re: Flippin-Out]
#13519503
04/15/20 07:42 PM
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Joined: Oct 2006
Posts: 96,187
Bigbob_FTW
OP
Big Sprocket Bob
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OP
Big Sprocket Bob
Joined: Oct 2006
Posts: 96,187 |
Looking at either illustration, do you know the x/y coordinates of each of the 3 points connected by the dashed lines? And the goal is to calculate x/y coordinates of the floating point?
FJB
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Re: Math Prodigy's
[Re: Bigbob_FTW]
#13519509
04/15/20 07:47 PM
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Joined: Feb 2015
Posts: 4,730
Flippin-Out
TFF Team Angler
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TFF Team Angler
Joined: Feb 2015
Posts: 4,730 |
Ahhh, you need the center of a circle that includes an arc, NOT the centerpoint along the length of an arc. Those are two different solutions. I'll sharpen my crayon with the illustration in front of me.
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